Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.6 Double-angle and Half-angle Formulas - 7.6 Assess Your Understanding - Page 497: 38

Answer

$\frac{\sqrt {15}}{8}$

Work Step by Step

Step 1. Using the given figures, we have $a=-\sqrt {5-4}=-1, b=-\sqrt {1-\frac{1}{16}}=-\frac{\sqrt {15}}{4}$ Step 2. $f(2\alpha)=sin(2\alpha)=2sin(\alpha)cos(\alpha)=2(-\frac{\sqrt {15}}{4})(-\frac{1}{4})=\frac{\sqrt {15}}{8}$
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