Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.6 Double-angle and Half-angle Formulas - 7.6 Assess Your Understanding - Page 497: 24

Answer

$ \sqrt 2-1$

Work Step by Step

$tan(\frac{9\pi}{8})=\frac{1-cos(\frac{9\pi}{4})}{sin(\frac{9\pi}{4})}=\frac{1-\frac{\sqrt 2}{2}}{\frac{\sqrt 2}{2}}=\sqrt 2-1$
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