Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.6 Double-angle and Half-angle Formulas - 7.6 Assess Your Understanding - Page 497: 30

Answer

$ \frac{\sqrt {2-\sqrt 2}}{2}$

Work Step by Step

$cos(-\frac{3\pi}{8})=cos(\frac{3\pi}{8})=\sqrt {\frac{1+cos(\frac{3\pi}{4})}{2}}=\sqrt {\frac{1-\frac{\sqrt 2}{2}}{2}}=\frac{\sqrt {2-\sqrt 2}}{2}$
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