Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.6 Double-angle and Half-angle Formulas - 7.6 Assess Your Understanding - Page 497: 22

Answer

$\frac{\sqrt{2+\sqrt2}}{2}.$

Work Step by Step

By the identity $\cos{(\frac{\alpha}{2})}=\sqrt{\frac{1+\cos{(\alpha)}}{2}}$. Hence $\cos{(22.5^{o})}=\sqrt{\frac{1+\cos{(45^{o})}}{2}}=\sqrt{\dfrac{1+\frac{\sqrt2}{2}}{2}}=\sqrt{\frac{2+\sqrt2}{4}}=\frac{\sqrt{2+\sqrt2}}{2}.$
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