Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - Chapter Review - Review Exercises - Page 434: 7

Answer

$-3\sqrt2-2\sqrt3$.

Work Step by Step

$6\cos{\frac{3\pi}{4}}+2\tan{\frac{-\pi}{3}}=6\frac{-\sqrt2}{2}-2\sqrt3=-3\sqrt2-2\sqrt3$.
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