Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - Chapter Review - Review Exercises - Page 434: 34

Answer

Amplitude:$2$, period: $\frac{2}{3}$.

Work Step by Step

If a function has form $y=A\sin(\omega x)$, then there $|A|$ stands for the amplitude. First we identify $\omega$ and $A$ from the form of $y=A\sin\omega x$. Hence $A=|-2|=2$, $\omega=3\pi.$ To get the period we can use the formula: $T=\frac{2\pi}{\omega}=\frac{2\pi}{3\pi}=\frac{2}{3}.$
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