Answer
$1$
Work Step by Step
Recall:
$\sec\theta=\frac{1}{\cos\theta}$.
Hence,
$\sec(50^{o})\cdot \cos(50^{o})=\frac{1}{\cos(50^{o})}\cdot \cos(50^{o})=1$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 6 - Trigonometric Functions - Chapter Review - Review Exercises - Page 434: 12
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