Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - Chapter Review - Review Exercises - Page 434: 12



Work Step by Step

Recall: $\sec\theta=\frac{1}{\cos\theta}$. Hence, $\sec(50^{o})\cdot \cos(50^{o})=\frac{1}{\cos(50^{o})}\cdot \cos(50^{o})=1$
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