Answer
Amplitude:$1$, period: $\pi$.
Work Step by Step
If a function has form $y=A\sin(\omega x)$, then there $|A|$ stands for the amplitude.
First we identify $\omega$ and $A$ from the form of $y=A\sin\omega x$.
Hence $A=|1|=1$, $\omega=2.$
To get the period we can use the formula: $T=\frac{2\pi}{\omega}=\frac{2\pi}{2}=\pi.$
