Answer
$-1$
Work Step by Step
We know that $\sin$ is an odd function, which means $f(-\theta)=-f(\theta).$
Hence $\frac{sin(-40^{o})}{\sin(40^{o})}=\frac{-\sin(40^{o})}{\sin(40^{0})}=-1.$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 6 - Trigonometric Functions - Chapter Review - Review Exercises - Page 434: 14
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
