Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding - Page 395: 92



Work Step by Step

We know that $\cot$ has a period of $\pi$, hence $\cot(\theta)=\cot(\theta+k\pi)$ where $k$ is an integer. Therefore, $\cot(\theta)+\cot(\theta-\pi)+\cot(\theta-2\pi)\\ =\cot(\theta)+\cot(\theta)+\cot(\theta)\\ =-2+(-2)+(-2)\\ =-6$
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