Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding - Page 395: 81



Work Step by Step

RECALL: $\tan \alpha =\dfrac {\sin \alpha }{\cos \alpha }$ Thus, $\tan \alpha -\dfrac {\sin \alpha }{\cos \alpha } \\=\dfrac {\sin \alpha }{\cos \alpha }-\dfrac {\sin \alpha }{\cos \alpha } \\=0$ Therefore, $\tan 40^o-\dfrac {\sin 40^o}{\cos 40^o}=0$
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