Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding - Page 395: 89

Answer

$0.9$

Work Step by Step

We know that $\sin$ has a period of $2\pi$, hence $\sin(\theta)=\sin(\theta+2k\pi)$ where $k$ is an integer. Therefore, $\sin(\theta)+\sin(\theta+2\pi)+\sin(\theta+4\pi)\\ =\sin(\theta)+\sin(\theta)+\sin(\theta)\\ =0.3+0.3+0.3\\ =0.9$
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