Answer
$0$
Work Step by Step
RECALL:
$\cot \alpha =\dfrac {\cos \alpha }{\sin \alpha }$
Thus,
$\cot \alpha -\dfrac {\cos \alpha }{\sin \alpha }=\cot{\alpha}-\cot{\alpha}=0$
Therefore,
$\cot 20^o-\dfrac {\cos 20^o}{\sin 20^o}=0$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding - Page 395: 82
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