Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding: 82

Answer

$0$

Work Step by Step

RECALL: $\cot \alpha =\dfrac {\cos \alpha }{\sin \alpha }$ Thus, $\cot \alpha -\dfrac {\cos \alpha }{\sin \alpha }=\cot{\alpha}-\cot{\alpha}=0$ Therefore, $\cot 20^o-\dfrac {\cos 20^o}{\sin 20^o}=0$
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