Answer
$1$
Work Step by Step
We know that $\sec^2\theta=1+\tan^2\theta$.
This means that $\sec^2{\theta}-\tan^2{\theta}=1$.
Hence,
$\sec^2 18^{o}-\tan^{2} 18^{o}=1$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding - Page 395: 78
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