Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding - Page 395: 78



Work Step by Step

We know that $\sec^2\theta=1+\tan^2\theta$. This means that $\sec^2{\theta}-\tan^2{\theta}=1$. Hence, $\sec^2 18^{o}-\tan^{2} 18^{o}=1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.