Answer
$(-\infty,-1] \cup [1,\infty).$
Work Step by Step
For any value of $\theta$ for which $\sec$ is defined, $-\infty\lt \sec\theta$ or $\infty\gt \sec\theta$, hence the range is $(-\infty,-1] \cup [1,\infty).$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding - Page 395: 105
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