Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - Chapter Review - Review Exercises - Page 345: 24

Answer

$ 2ln(2x+3)-2ln(x-1)-2ln(x-2)$

Work Step by Step

$ln(\frac{2x+3}{x^2-3x+2})^2=2ln(\frac{2x+3}{x^2-3x+2})=2ln(\frac{2x+3}{(x-1)(x-2)})=2ln(2x+3)-2ln(x-1)-2ln(x-2)$
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