Answer
$x \gt \dfrac{2}{3}$
Work Step by Step
We know that by definition if $\log_a{b}$, then $b\gt0$.
Hence here,
$3x-2 \gt 0$
Thus,
\begin{align*}
3x &\gt 2\\\\
\frac{3x}{3} &\gt \frac{2}{3}\\\\
x &\gt \frac{2}{3}
\end{align*}
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - Chapter Review - Review Exercises - Page 345: 16
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