Answer
(a) $x=-2$ and $x=4$.
(b) $x=0$ and $x=6$.
Work Step by Step
(a) Given $h(x)=(x+2)(x-4)^3$, we can identify, by letting $h(x)=0$, the x-intercept as $x=-2$ and $x=4$.
(b) The graph of $y=h(x-2)$ can be obtained from $h(x)$ by shifting the curve 2 units to the right, thus the x-intercepts for $y=h(x-2)$ become $x=0$ and $x=6$.
