Answer
$f(x)=x^3(x+4)(x-2)$
Work Step by Step
Step 1. Use the given zeros and multiplicities, we can write a general form of the function as $f(x)=ax^3(x+4)(x-2)$ where $a$ is unknown.
Step 2. With known point $(-2,64)$ on the curve, we have $f(-2)=a(-2)^3(-2+4)(-2-2)=64$, thus $a=1$
Step 3. Thus the function is $f(x)=x^3(x+4)(x-2)$