Answer
(a) $x=-3$ and $x=2$.
(b) $x=-6$ and $x=-1$.
Work Step by Step
(a) Given $G(x)=(x+3)^2(x-2)$, we can identify, by letting $G(x)=0$, the x-intercept as $x=-3$ and $x=2$.
(b) The graph of $y=G(x+3)$ can be obtained from $G(x)$ by shifting the curve 3 units to the left, thus the x-intercepts for $y=G(x+3)$ become $x=-6$ and $x=-1$.