Answer
$f(x)=-2(x+5)^2(x-2)(x-4)$
Work Step by Step
Step 1. Given zeros and multiplicities, we can write a general form of the function as $f(x)=a(x+5)^2(x-2)(x-4)$ where $a$ is unknown.
Step 2. With known point $(3,128)$ on the curve, we have $f(3)=a(3+5)^2(3-2)(3-4)=128$, thus $a=-2$
Step 3. Thus the function is $f(x)=-2(x+5)^2(x-2)(x-4)$