Answer
$f(x)=-2(x+4)(x+1)(x-2)$
Work Step by Step
Step 1. Given zeros $x=-4,-1,2$, we can write a general form of the function as $f(x)=a(x+4)(x+1)(x-2)$ where $a$ is unknown.
Step 2. With y-intercept $(0,16)$, we have $f(0)=a(0+4)(0+1)(0-2)=16$, thus $a=-2$
Step 3. Thus the function is $f(x)=-2(x+4)(x+1)(x-2)$