Answer
$y=x^2 -1$
Work Step by Step
$y=x^2 -1$
$y=(x-0)^2 -1$
vertex $(0,-1) $
$x$ intercept: $y=x^2-1$
$\qquad \qquad \enspace 0=x^2-1$
$\qquad \qquad \enspace 1=x^2$
$\qquad \qquad \pm1=x$
$ \qquad \qquad(-1,0)$ and $(1,0)$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 3 - Linear and Quadratic Functions - 3.1 Properties of Linear Functions and Linear Models - 3.1 Assess Your Understanding - Page 126: 1
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