## Precalculus (10th Edition)

$200$
We know that $a_n=a_1+(n-1)d.$ where $d$=common difference and $a_1$= the first term Here $a_1=2$ and $d=a_2-a_1=2$ Hence, here we have $a_n=2+(n-1)\cdot2.$ Therefore $a_{100}=2+(100-1)\cdot2\\=200.$