Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.2 Arithmetic Sequences - 12.2 Assess Your Understanding - Page 814: 18

Answer

$a_n=4n-6.$ $a_{51}=198.$

Work Step by Step

We know that the $n^{th}$ term $a_n$ of an arithmetic sequence is given by the formula $a_n=a_1+(n-1)d$ where $d$=common difference and $a_1$= the first term Hence, here we have $a_n=-2+(n-1)4\\a_n=-2+4n-4\\a_n=4n-6.$ Therefore $a_{51}=4\cdot51-6\\a_{51}=204-6\\a_{51}=198.$
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