Precalculus (10th Edition)

$a_n=3n-1$ $a_{51}=152$
We know that the $n^{th}$ term $a_n$ of an arithmetic sequence is given by the formula $a_n=a_1+(n-1)d$ where $d$=common difference and $a_1$= the first term Hence, here we have $a_n=2+(n-1)3\\ a_n=2+3n-3\\ a_n=3n-1$ Therefore, $a_{51}=3\cdot51-1\\ a_{51}=153-1\\ a_{51}=152$