Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 1 - Graphs - 2.1 Functions - 2.1 Assess Your Understanding - Page 58: 93

Answer

$A=-\frac{7}{2}$

Work Step by Step

We plug in $x=2$ to $f(x)$ to get $f(2)=2\cdot2^3+A\cdot2^2+4\cdot2-5 \\5=2(8)+A(4)+8-5 \\5=16+4A+3 \\5=4A+19 \\5-19=4A \\-14=4A \\-\frac{14}{4}=\frac{4A}{4} \\-\frac{7}{2}=A$
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