Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 1 - Graphs - 2.1 Functions - 2.1 Assess Your Understanding - Page 58: 92

Answer

$x=\dfrac{3}{8}$

Work Step by Step

With $f(x)=-\frac{7}{16}$, substitute $-\frac{7}{16}$ to $f(x)$ to obtain: $$-\dfrac{7}{16}=\dfrac{5}{6}x-\dfrac{3}{4}$$ Multiply $48$ to both sides of the equation to eliminate the fractions: $$\begin{align*} 48\left(-\dfrac{7}{16}\right)&=\left(\dfrac{5}{6}x-\dfrac{3}{4}\right)\cdot 48\\ -21&=40x-36 \end{align*}$$ Add $36$ to both sdies: $$\begin{align*} -21+36&=40x-36+36\\ 15&=40x \end{align*}$$ Divide $40$ to both sides: $$\begin{align*} \frac{15}{40}&=\frac{40x}{40}\\ \frac{3}{8}&=x \end{align*}$$
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