Answer
$\dfrac{x(3x+2)}{(3x+1)^2}$
Work Step by Step
Use distributive property.
$\dfrac{(3x+1)\cdot 2x-x^2\cdot 3}{(3x+1)^2}\\
=\dfrac{6x^2+2x-3x^2}{(3x+1)^2}$
Simplify by combining like terms.
$=\dfrac{3x^2+2x}{(3x+1)^2}$
Factor the numerator.
$=\dfrac{x(3x+2)}{(3x+1)^2}$
Hence, the lowest term is $\dfrac{x(3x+2)}{(3x+1)^2}$.
