Answer
$\dfrac{x^2+4}{(x+2)^2(x-2)^2}$.
Work Step by Step
Use distributive property.
$\frac{x\cdot 2x-(x^2-4)\cdot 1}{(x^2-4)^2}\\
=\dfrac{2x^2-(x^2-4)}{(x^2-4)^2}\\
=\dfrac{2x^2-x^2+4}{(x^2-4)^2}$
Simplify by combining like terms.
$=\dfrac{x^2+4}{(x^2-4)^2}$
Hence, the lowest term is $\dfrac{x^2+4}{(x^2-4)^2}$.
