Answer
$\dfrac{19}{(3x-5)^2}$
Work Step by Step
Use the distributive property:
$\dfrac{(2x+3)\cdot 3-(3x-5)\cdot 2}{(3x-5)^2}\\
\\=\dfrac{6x+9-(6x-10)}{(3x-5)^2}\\
\\=\dfrac{6x+9-6x+10}{(3x-5)^2}$
Simplify.
$=\dfrac{19}{(3x-5)^2}$
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