Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.5 Rational Expressions - A.5 Assess Your Understanding - Page A42: 37

Answer

$\dfrac{19}{(3x-5)^2}$

Work Step by Step

Use the distributive property: $\dfrac{(2x+3)\cdot 3-(3x-5)\cdot 2}{(3x-5)^2}\\ \\=\dfrac{6x+9-(6x-10)}{(3x-5)^2}\\ \\=\dfrac{6x+9-6x+10}{(3x-5)^2}$ Simplify. $=\dfrac{19}{(3x-5)^2}$
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