Answer
$\dfrac{x+1}{x-1}$
Work Step by Step
Multiply the numerator and the denominator by $x$.
$=\dfrac{x(1+\frac{1}{x})}{x(1-\frac{1}{x})}$
Use distributive property.
$=\dfrac{x+x\cdot \frac{1}{x}}{x-x\cdot \frac{1}{x}}$
Simplify.
$=\dfrac{x+1}{x-1}$
Hence, the lowest term is:
$\dfrac{x+1}{x-1}$
