Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 4 - Exponential Functions - 4.2 Comparing Exponential and Linear Functions - Exercises and Problems for Section 4.2 - Exercises and Problems - Page 155: 32

Answer

$p(x)=20(1.0718)^x$ $q(x)=160(0.8706)^x $

Work Step by Step

Let $p(x)=a(b)^x $ for the increasing exponential function as shown in the figure. The value of $a$ can be read directly from the figure as $a= 20$. We now have $p= 20(b)^x$. Use the point (10,40) on the graph to find the value of $b$. $$ \begin{aligned} p(10) & =40 \\ 20 b^{10} & =40 \\ b^{10} & =2 \\ b & =2^{1 / 10} \\ & =1.0718 \end{aligned} $$ Hence, $p(x)=20(1.0718)^x $ Let $q(x)=a(b)^x $ for the decreasing exponential function as shown in the figure. The values of $a$ and $b$ can be found from the points, $(10,40)$ and $(15, 20)$ . We make use of the ratio of $ q(10)=40$, and $q(15)=20$ $$ \begin{aligned} \frac{a b^{15}}{a b^{10}} & =\frac{g(15)}{g(10)} \\ b^5 & =\frac{20}{40} \\ b & =\left(\frac{20}{40}\right)^{1 / 5} \\ & =(0.5)^{1 / 5}=0.8706 \end{aligned} $$ and $$ \begin{aligned} a\left((0.5)^{1 / 5}\right)^{10} & =40 \\ a & =\frac{40}{(0.5)^2} \\ & =160 . \end{aligned} $$ Hence, $q(x)=160(0.8706)^x $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.