Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 3 - Quadratic Functions - 3.2 The Vertex of a Parabola - Exercises and Problems for Section 3.2 - Exercises and Problems - Page 128: 44

Answer

a)This is because $h(t)$ must be positive since it describes the height of the ballet dancer. b) At $t=T / 2$ c) $4 T^2$

Work Step by Step

a) This is because $h(t)$ must be positive since it describes the height of the ballet dancer. Note that $h(t)=-16 t^2+16 T t=16 t(T-t)$. b) The times $t=0$ and $t=T$ give the start and end of the jump. The maximum height occurs halfway in between, at $t=T / 2$. c) The maximum height is $$ h\left(\frac{T}{2}\right)=16\left(\frac{T}{2}\right)\left(T-\frac{T}{2}\right)=4 T^2 . $$
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