Answer
$
y=(x-3)^2+4
$
Work Step by Step
The coordinates of the point $(6,13)$ must satisfy the equation, so
$$
\begin{aligned}
& 13=(6-3)^2+k \\
& 13=9+k \\
& k=4 \\
\end{aligned}
$$ Hence $$
y=(x-3)^2+4
$$
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 3 - Quadratic Functions - 3.2 The Vertex of a Parabola - Exercises and Problems for Section 3.2 - Exercises and Problems - Page 128: 27
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