Chapter 3 - Quadratic Functions - 3.2 The Vertex of a Parabola - Exercises and Problems for Section 3.2 - Exercises and Problems - Page 128: 24

See graph

Not that $m(n-17)-159=\frac{1}{2}(n-17)^2-159=\left(\frac{1}{2} n^2-17 n+\frac{289}{2}\right)-159=\frac{1}{2} n^2-17 n-\frac{29}{2}$. To sketch, shift the graph of $m(n)=\frac{1}{2} n^2$ by 17 units to the right and 159 units down, as in the figure.