Answer
$
y=\frac{1}{4}\cdot(x-7)^2+3
$
Work Step by Step
We have $(h, k)=(7,3)$, and $y=a(x-7)^2+3$. Solve for $a$
$$
\begin{aligned}
a(3-7)^2+3 & =7 \\
16a & =4 \\
a & =\frac{1}{4}
\end{aligned}
$$ Hence $$
y=\frac{1}{4}\cdot(x-7)^2+3
$$
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 3 - Quadratic Functions - 3.2 The Vertex of a Parabola - Exercises and Problems for Section 3.2 - Exercises and Problems - Page 128: 33
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