Answer
See graph
Work Step by Step
Not that $m(n)+\sqrt{13}=\frac{1}{2} n^2+\sqrt{13}$.
To sketch, shift the graph of $m(n)=\frac{1}{2} n^2$ up $\sqrt{13}$ units, as in the figure.
Functions Modeling Change: A Preparation for Calculus, 5th Edition
by Connally, Eric; Hughes-Hallett, Deborah; Gleason, Andrew M.; Cheifetz, Phil C.
Published by
Wiley
ISBN 10:
1118583191
ISBN 13:
978-1-11858-319-7
Chapter 3 - Quadratic Functions - 3.2 The Vertex of a Parabola - Exercises and Problems for Section 3.2 - Exercises and Problems - Page 128: 21
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