Answer
See graph
Work Step by Step
Factor out the coefficient of $x^2$ and square half of the coefficient of the $x$-term: $(60 / 2)^2=30^2=900$. Adding and subtracting this number after the $x$-term gives
$$
\begin{aligned}
& y=0.03 x^2+1.8 x+2 \\
& y=0.03\left(x^2+60 x+\frac{200}{3}\right) \\
& y=0.03\left(x^2+60 x+30^2+\frac{200}{3}-900\right)\\
& y=0.03(x+30)^2-25
\end{aligned}
$$
i) The vertex is $(-30,-25)$ and the axis of symmetry is $x=-30$.
ii) From the original equation, the $y$-intercept is $y= 2$.
iii) We find the $x$-intercepts by solving $y=0$
$$
\begin{aligned}
0.03(x+30)^2-25 & =0 \\
0.03(x+30)^2 & =25 \\
(x+30)^2 & =\frac{25}{0.03} \\
& =\frac{2500}{3} \\
x & =-30 \pm \sqrt{\frac{2500}{3}}
\end{aligned}
$$
$$
x=-1.132, x=-58.868
$$
See graph.
