Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 3 - Quadratic Functions - 3.1 Introduction to the Family of Quadratic Functions - Exercises and Problems for Section 3.1 - Exercises and Problems - Page 121: 7

Answer

Yes

Work Step by Step

Simplifying the expression: $$\sqrt{5}+\sqrt{3n^4}-\sqrt{\frac{n^4}{4}} \\ \sqrt{5}+\sqrt{3}n^2-\frac{n^2}{2} \\ 1.23n^2+\sqrt5$$ It is a quadratic function.
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