Answer
$y=-\frac{5}{12} x^2-\frac{5}{3} x+5$
Work Step by Step
We know there are zeros at $x=-6$ and $x=2$, so we use the factored form:
$$
y=a(x+6)(x-2)
$$
We solve for $a$ by substituting $x=0, y=5$,this gives
$$
\begin{aligned}
5 & =a(0+6)(0-2) \\
5 & =-12 a \\
a & =-\frac{5}{12}
\end{aligned}
$$ Hence $$
\begin{aligned}
y & =-\frac{5}{12}(x+6)(x-2) \\
y & =-\frac{5}{12} x^2-\frac{5}{3} x+5
\end{aligned}
$$
