Answer
$
y=\frac{6}{7}(x+1)(x-5)
$
Work Step by Step
We know there are zeros at $x=-1$ and $x=5$, so we use the factored form:
$$
y=a(x+1)(x-5)
$$
We solve for $a$ by substituting $x=-2, y=6$,this gives
$$
\begin{aligned}
6 & =a(-2+1)(-2-5)\\
6 & =7 a \\
a & =\frac{6}{7}
\end{aligned}
$$ Hence $$
y=\frac{6}{7}(x+1)(x-5)
$$
