Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 3 - Quadratic Functions - 3.1 Introduction to the Family of Quadratic Functions - Exercises and Problems for Section 3.1 - Exercises and Problems - Page 121: 30

Answer

Since rates of change are decreasing, the graph of $f(x)$ is concave down.

Work Step by Step

Calculate the rate of change between the following points of length 2.$(x_1, x_2)= (-1,1)$ ,$(x_2, x_3)= (1,3)$ and $(x_3, x_4)= (3,5)$ $$ \begin{aligned} & \frac{\Delta f(x)}{\Delta x}=\frac{f(1)-f(-1)}{1-(-1)}=\frac{\left(4-1^2\right)-\left(4-(-1)^2\right)}{2}=0 . \\ & \frac{\Delta f(x)}{\Delta x}=\frac{f(3)-f(1)}{3-1}=\frac{\left(4-3^2\right)-\left(4-1^2\right)}{2}=-4 . \\ & \frac{\Delta f(x)}{\Delta x}=\frac{f(5)-f(3)}{5-3}=\frac{\left(4-5^2\right)-\left(4-3^2\right)}{2}=-8 . \end{aligned} $$ Since rates of change are decreasing, the graph of $f(x)$ is concave down.
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