Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review: 34

Answer

$\frac{y}{2}$

Work Step by Step

We can simplify by canceling out common factors of both fractions and then multiplying. $\frac{27y^3}{21}\times\frac{7}{18y^2} =\frac{/\!\!3\times/\!\!9\times y\times /\!\!y^2}{/\!\!3\times/\!\!7}\times \frac{/\!\!7}{2\times/\!\!9\times /\!\!y^2}=\frac{y}{2}$
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