Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review - Page 319: 20



Work Step by Step

$15=\underline3\times5$ $27=\underline3\times3\times3$ GCF=3 $\frac{15}{27}=\frac{15\div3}{27\div3}=\frac{5}{9}$
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