Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review - Page 319: 25



Work Step by Step

$45x^2y=\underline3\times\underline3\times5\times \underline x\times x\times \underline y$ $27xy^3=\underline3\times\underline3\times3\times \underline x\times \underline y\times y\times y$ GCF=$3\times3\times x\times y=9xy$ $\frac{45x^2y}{27xy^3}=\frac{45x^2y\div9xy}{27xy^3\div9xy}=\frac{5x}{3y^2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.