Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review - Page 319: 41



Work Step by Step

$x\div y=\frac{9}{7}\div\frac{3}{4}=\frac{9}{7}\times\frac{4}{3}=\frac{9\times4}{7\times3}=\frac{36}{21}=\frac{36\div3}{21\div3}=\frac{12}{7}=1\frac{5}{7}$
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