Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review - Page 319: 22

Answer

$-\frac{y^2}{2}$

Work Step by Step

$36y^3=\underline6\times\underline6\times\underline y\times y\times y$ $72y=2\times\underline6\times\underline6\times\underline y$ GCF=$6\times6\times y=36y$ $-\frac{36y^3}{72y}=-\frac{36y^3\div36y}{72y\div36y}=-\frac{y^2}{2}$
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