Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review - Page 319: 26



Work Step by Step

$42ab^2c=\underline2\times\underline3\times7\times \underline a\times b\times \underline b \times \underline c$ $30abc^3=\underline2\times\underline3\times5\times \underline a\times \underline b\times \underline c\times c\times c$ GCF=$2\times3\times a\times b\times c=6abc$ $\frac{42ab^2c}{30abc^3}=\frac{42ab^2c\div6abc}{30abc^3\div6abc}=\frac{7b}{5c^2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.