Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 12 - Statistics - 12.3 Measures of Dispersion - Exercise Set 12.3 - Page 800: 7

Answer

See below.

Work Step by Step

The deviation is the difference of the data item and the mean. a) Hence here the deviations: $3-12=-9,5-12=-7,7-12=-5,12-12=0, 18-12=6, 27-12=15$ b) The sums of the deviations: $-9+(-7)+(-5)+6+15=0$
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